[TIP] Can you mock a function that has a decorator applies to it?

[Brianna Laugher]

Hi,

On 5 July 2012 03:35, John Wong <gokoproject at gmail.com> wrote:
> There are times when decorator really shine and I don't see a way to Mock
> out the decorator. I know it replaces the current function.... is there a
> way out of this?

Can't you just call the decorator on your mocked function explicitly?
'@foo' is just syntactic sugar for 'fn = foo(fn)' anyway right?

I put a simple example with 'property' here:

https://gist.github.com/3050354

Hope that explains it, not sure if you are trying to do something more
complicated than that.

cheers
Brianna


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